JEE MAIN - Physics (2024 - 8th April Morning Shift - No. 7)
The output $$\mathrm{Y}$$ of following circuit for given inputs is :
_8th_April_Morning_Shift_en_7_1.png)
$$A \cdot B$$
$$\bar{A} \cdot B$$
$$\Lambda \cdot B(\Lambda+B)$$
0
Wyjaśnienie
_8th_April_Morning_Shift_en_7_2.png)
The output $$\mathrm{Y}$$ of following circuit for given inputs is :